Prove that-cos 2-4-sin 2-4-sin 2 -

LHS = cos^2 (π/4 θ ) sin^2 (π/4 θ ) = cos^2 (π/4 θ ) [∵ cos 2 θ = cos^2 θ sin^2 θ ] = cos (π/2 2 θ ) [ ∵ cos (π/2 θ ) = sin θ ] = sin 2 θ = RHS ...

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Sin2A and Cos2A in Terms of tanA

Prove that:co...

Question

Prove that:

$c o s^{2} (\frac{π}{4} - θ) - s i n^{2} (\frac{π}{4} - θ) = s i n 2 θ$

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θ

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