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Question

Prove that :
cos2θ(1+tan2θ)=1.

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Solution

We have,
LHS = cos2θ(1+tan2θ)
LHS=cos2θsec2θ [1+tan2θ=sec2θ]
LHS=cos2θ(1cos2θ) [secθ=1cosθ]
LHS = 1 = RHS

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