Prove that- cos 35 -A-cos 35 -B-sin 35 -A-sin 35 -B -cosA-B

LHS=cos( 35 ^∘ #160; +A)cos( 35 ^∘ #160; B)+sin( 35 ^∘ #160; +A)sin( 35 ^∘ #160; B)=cos (35^∘+A 35^∘+B) =cos(A+B)=RHS ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Basic Inverse Trigonometric Functions

Prove that: ...

Question

Prove that: $c o s (35^{\circ} + A) . c o s (35^{\circ} - B) + s i n (35^{\circ} + A) . s i n (35^{\circ} - B) = c o s (A + B)$

Open in App

Solution

Suggest Corrections

Similar questions

s i n 35^{\circ} s i n 55^{\circ} - c o s 35^{\circ} c o s 55^{\circ} = 0

(sin 35^{0} cos 55^{0} + cos 35^{0} sin 55^{0}) + \sqrt{3} (tan 10^{0} tan 30^{0} tan 80^{0}) = 2

Without using tables, show that (cos $35^{\circ}$ cos $55^{\circ}$ - sin $35^{\circ}$ sin $55^{\circ}$ ) = 0

Prove that cos(A-B)-cos(A+B)=2sinAsinB

Prove that $\frac{1 - cos A + cos B - cos (A + B)}{1 + cos A - cos B - cos (A + B)} = tan \frac{A}{2} cot (\frac{B}{2})$ .

Join BYJU'S Learning Program