Prove that:
$c o s 4 x = 1 - 8 s i n^{2} x c o s^{2} x$

Open in App

Solution

$c o s 4 x = 1 - 2 s i n^{2} 2 x = 1 - 2 (2 s i n x c o s x)^{2} = 1 - 8 s i n^{2} x c o s^{2} x$

Suggest Corrections

Similar questions

cos 4 x = 1 - 8 {sin}^{2} x {cos}^{2} x

c o s 4 x = 1 - 8 s i n^{2} x c o s^{2} x

cos 4x = 1 – 8sin²x cos²x

c o s 4 x = 1 - 8 s i n^{2} x . c o s^{2} x

cos 4 x = 1 - 8 {sin}^{2} x {cos}^{2} x

Join BYJU'S Learning Program