Prove that 2 A 2 B- 2 B 2 A- 2 A- 2 B

LHS =^2A ^2B ^2B ^2A #160; #160; #160; #160; =^2A(1+^2B) ^2B(1+^2A) #160; #160; #160; #160; #160; #160; #160; #160 ...

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Trigonometric Identities

Prove that ...

Question

Prove that ${cot}^{2} A {csc}^{2} B - {cot}^{2} B {csc}^{2} A = {cot}^{2} A - {cot}^{2} B$

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(a + b)^{2} + (a - b)^{2}

2 a + 2 b

2 a - 2 b

2 a^{2} + 2 b^{2}

2 a^{2} + 2 b^{2}

{tan}^{2} A {sec}^{2} B - {sec}^{2} A {tan}^{2} B = {tan}^{2} A - {tan}^{2} B

c o t^{2} A c o s e c^{2} B - c o t^{2} B c o s e c^{2} A = c o s e c^{2} A - c o s e c^{2} B

{sin}^{2} A {cos}^{2} B - {cos}^{2} A {sin}^{2} B = {sin}^{2} A - {sin}^{2} B

Prove that

Cot²A × cosec²A - cot²B × cosec² B = cot²A - cot² B

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