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Calculating Heights and Distances

Prove that : ...

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Prove that : cot^2 x . (sec x - 1)/(1 + sin x) + sec^2 x . (sin x -1)/(1 + sec x) = 0

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Q. Prove that :

\frac{1}{sec x - tan x} - \frac{1}{sec x} = tan x (1 + sin x)

\sqrt{\frac{1 + sin x}{1 - sin x}} = sec x + tan x

\frac{sec x + 1 - tan x}{tan x + sec x + 1} = \frac{1 - sin x}{cos x}

sec x \sqrt{1 - {sin}^{2} x} = 1

sin x (1 + tan x) + cos x (1 + cot x) = sec x + c o s e c x

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Calculating Heights and Distances

Standard IX Mathematics

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