Prove that- 7 12o -2-3-4-6-

( 15 2 #160; ) #160; =cos( 15/2 ) #160; #160; sin( 15/2 ) #160; #160; = 2cos ^ 2 ( 15/2 ) #160; #160; 2sin( 15/2 ) #160; ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sin(A+B)Sin(A-B)

Prove that: ...

Question

Prove that:
$cot (7 {\frac{1}{2}}^{o}) = \sqrt{2} + \sqrt{3} + \sqrt{4} + \sqrt{6}$ .

Open in App

Solution

Suggest Corrections

Similar questions

cot 7 {\frac{1}{2}}^{\circ} = \sqrt{2} + \sqrt{3} + \sqrt{4} + \sqrt{6} .

7 {\frac{1}{2}}^{\circ}

82 {\frac{1}{2}}^{\circ}

(\sqrt{3} + \sqrt{2}) (\sqrt{2} + 1)

\sqrt{2} + \sqrt{3} + \sqrt{4} + \sqrt{6}

\begin{matrix} List 1 & List 2 Complex Ions & Magnetic Moment Bohr magneton a . [F e (C N)_{6}]^{- 4} & 1. 1.73 b . [T i (H_{2} O)_{6}]^{3 +} & 2. 5.93 c . [C r (H_{2} O)_{6}]^{3 +} & 3. 0.00 d . N i (H_{2} O)_{6}]^{2 +} & 4. 2.83 e . [F e F_{6}]^{- 3} & 5. 3.88 \end{matrix}

Codes :

c o t 7 \frac{1^{\circ}}{2} = \sqrt{2} + \sqrt{3} + \sqrt{4} + \sqrt{6}

tan \frac{11 π}{3} - 2 sin \frac{4 π}{6} - \frac{3}{4} cos e c^{2} \frac{π}{4} + 4 {cos}^{2} \frac{17 π}{6} = \frac{3 - 4 \sqrt{3}}{2}

Join BYJU'S Learning Program