Prove that- 0-60 - 0-1-138-1323 - 13-1 - -32

To nbsp;Prove: (0.6)^0 (0.1)^ 1(38)^ 1(32)^3 ( 13)^ 1 = 32 LHS = nbsp;(0.6)^0 (0.1)^ 1(38)^ 1(32)^3 ( 13)^ 1 =1 (110)^ 183×3^3 2^3 (13)^ 1 =1 ...

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Byju's Answer

Standard XII

Mathematics

Definition of Relations

Prove that: 0...

Question

Prove that: $\frac{(0.6)^{0} - (0.1)^{- 1}}{{(\frac{3}{8})}^{- 1} {(\frac{3}{2})}^{3} - {(\frac{1}{3})}^{- 1}} = - \frac{3}{2}$

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Solution

To Prove: $\frac{(0.6)^{0} - (0.1)^{- 1}}{{(\frac{3}{8})}^{- 1} {(\frac{3}{2})}^{3} - {(\frac{1}{3})}^{- 1}} = - \frac{3}{2}$

$LHS = \frac{(0.6)^{0} - (0.1)^{- 1}}{{(\frac{3}{8})}^{- 1} {(\frac{3}{2})}^{3} - {(\frac{1}{3})}^{- 1}}$

$= \frac{1 - {(\frac{1}{10})}^{- 1}}{\frac{8}{3} \times \frac{3^{3}}{2^{3}} - {(\frac{1}{3})}^{- 1}}$

$= \frac{1 - 10}{\frac{8}{3} \times \frac{27}{8} - 3}$

$= \frac{- 9}{9 - 3}$

$= \frac{- 9}{6}$

$= \frac{- 3}{2}$

$= RHS$
Hence, proved .

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