Prove that- 13-4-15-6-17-8- to -log 2-12

Now, 13.4+15.6+17.8+..... to ∞ =13 14+15 16+17 18+..... to ∞ =1 12+13 14+15 16+17 18+..... to ∞ 12 =log 2 12 [ Since ...

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nth Term of A.P

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Prove that:
$\frac{1}{3.4} + \frac{1}{5.6} + \frac{1}{7.8} + . . . . .$ to $\infty = log 2 - \frac{1}{2}$

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