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Question

Prove that 1+cosAsinA+sinA1+cosA=2cosecA.

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Solution

L.H.S.
1+cosAsinA+sinA1+cosA

=(1+cosA)2+sin2AsinA(1+cosA)

=1+cos2A+2cosA+sin2AsinA(1+cosA)

=2+2cosAsin(1+cosA)

=2(1+cosA)sinA(1+cosA)

=2sinA=2cosecA = R.H.S.

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