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Question

Prove that :-
1+cosθsinθ+sinθ1+cosθ=2.cosecθ

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Solution

L.H.S

1+cosθsinθ+sinθ1+cosθ

=(1+cosθ)2+sin2θsinθ(1+cosθ)

=1+cos2θ+2cosθ+sin2θsinθ(1+cosθ)

=1+cos2θ+sin2θ+2cosθsinθ(1+cosθ)(Since:sin2x+cos2x=1)

=1+1+2cosθsinθ(1+cosθ)

=2+2cosθsinθ(1+cosθ)

=2(1+cosθ)sinθ(1+cosθ)

=2sinθ

=2cscθ

Hence, proved.


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