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Question

Prove that (1+sinθ)2+(1sinθ)22cos2θ=(1+sin2θ1sin2θ)

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Solution

LHS=(1+sinθ)2+(1sinθ)22cos2θ

=1+sin2θ2sinθ+1+sin2θ+2sinθ2(1sin2θ)

=1+sin2θ1sin2θ

=RHS

Hence proved

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