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Byju's Answer
Standard X
Mathematics
Trigonometric Identities
Prove that : ...
Question
Prove that :
1
+
sin
θ
cos
θ
+
cos
θ
1
+
sin
θ
=
2
sec
θ
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Solution
1
+
s
i
n
θ
c
o
s
θ
+
c
o
s
θ
1
+
s
i
n
θ
=
2
s
e
c
θ
(
1
+
s
i
n
θ
)
2
+
c
o
s
2
θ
c
o
s
θ
(
1
+
s
i
n
θ
)
=
2
s
e
c
θ
1
+
s
i
n
2
θ
+
2
s
i
n
θ
+
c
o
s
2
θ
c
o
s
θ
(
1
+
s
i
n
θ
)
=
2
s
e
c
θ
s
i
n
2
θ
+
c
o
s
2
θ
=
1
1
+
1
+
2
s
i
n
θ
c
o
s
θ
(
1
+
s
i
n
θ
)
=
2
s
e
c
θ
2
+
2
s
e
c
θ
c
o
s
θ
(
1
+
s
i
n
θ
)
=
2
s
e
c
θ
2
(
1
−
1
s
i
n
θ
)
c
o
s
θ
(
1
+
s
i
n
θ
)
=
2
s
e
c
θ
2
s
e
c
θ
=
2
s
e
c
θ
L
.
H
.
S
=
R
.
H
.
S
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Similar questions
Q.
Prove the following trigonometric identities.
1
+
sin
θ
cos
θ
+
cos
θ
1
+
sin
θ
=
2
sec
θ