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Question

Prove that : 1+sinθcosθ+cosθ1+sinθ=2secθ

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Solution

1+sinθcosθ+cosθ1+sinθ=2secθ
(1+sinθ)2+cos2θcosθ(1+sinθ)=2secθ
1+sin2θ+2sinθ+cos2θcosθ(1+sinθ)=2secθ
sin2θ+cos2θ=1
1+1+2sinθcosθ(1+sinθ)=2secθ
2+2secθcosθ(1+sinθ)=2secθ
2(11sinθ)cosθ(1+sinθ)=2secθ
2secθ=2secθ L.H.S=R.H.S

1226200_1502817_ans_b0778e4c69eb495388810e41b2f7dabe.jpg

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