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Question

Prove that 1+sinθcosθ+cosθ1+sinθ=2secθ

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Solution

LHS=1+sinθcosθ+cosθ1+sinθ
=(1+sin2θ)2+cos2θcosθ(1+sinθ)

=1+sin2θ+2sinθ+cos2θcosθ(1+sinθ)

=2(1+sinθ)cosθ(1+sinθ)

=2secθ

=RHS

Hence proved

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