Prove that 1-sinA1-sinA-secA-tanA2

LHS : 1 sinA1+sinA =(1 sinA)^21 sin^2A =(1 sinA)^2cos^2A =(1 sinAcosA)^2 =(1cosA sinAcosA)^2 =(secA tanA)^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios of Compound Angles

Prove that ...

Question

Prove that $\frac{1 - s i n A}{1 + s i n A} = (s e c A - t a n A)^{2}$

Open in App

Solution

Suggest Corrections

Similar questions

{(s e c A - t a n A)}^{2} = \frac{1 - s i n A}{1 + s i n A}

\frac{{tan} A (cosecA - 1)}{1 + sin A} = secA

\sqrt{\frac{1 + s i n A}{1 - s i n A}} = s e c A + t a n A

\frac{c o t^{2} A (s e c A - 1)}{1 + s i n A} = s e c^{2} A (\frac{1 - s i n A}{1 + s e c A})

Prove the following trigonometric identities:

$(s e c A - t a n A)^{2} = \frac{1 - s i n A}{1 + s i n A}$

Join BYJU'S Learning Program