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Byju's Answer
Standard IX
Mathematics
Laws of Exponents for Real Numbers
Prove that : ...
Question
Prove that :
2
30
+
2
29
+
2
28
2
31
+
2
30
−
2
29
=
7
10
Open in App
Solution
2
30
+
2
29
+
2
28
2
31
+
2
30
−
2
29
=
2
28
(
2
2
+
2
1
+
1
)
2
29
(
2
2
+
2
1
−
1
)
=
2
28
(
4
+
2
+
1
)
2
29
(
4
+
2
−
1
)
=
2
28
(
7
)
2
29
(
5
)
applying
a
m
a
n
=
a
m
.
n
2
28
−
29
(
7
)
5
=
2
−
1
(
7
)
5
a
−
n
=
1
a
n
=
7
10
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16
Similar questions
Q.
Find the value of:
2
30
+
2
29
+
2
28
2
31
+
2
30
−
2
29
Q.
Simplify:
3
30
+
3
29
+
3
25
3
31
+
3
30
−
3
29
+
2
30
+
2
29
+
2
25
2
31
+
2
30
−
2
29
Q.
Consider two arbitrary decay equations and mark the correct alternative (s) given below
(I)
230
92
U
→
n
229
92
U
(II)
230
92
U
→
p
+
229
91
Pa
Given: M(
230
92
U
)
=
230.033927
u
,
M (
229
92
U
)
=
229.03349
u
,
m
n
=
1.008665
u
,
M (
229
91
Pa
)
=
229.032089
,
m
p
=
1.007825
,
1
a
m
u
=
931.5
MeV
Q.
Show that
230
92
U
does not decay be emitting a neutron or proton. Given:
M
(
230
92
U
)
=
230.033927
a
m
u
,
M
(
230
92
U
)
=
229.033496
a
m
u
,
M
(
229
92
P
a
)
=
229.032089
a
m
u
,
m
(
n
)
=
1.008665
a
m
u
,
m
(
p
)
=
1.007825
a
m
u
Q.
Consider two arbitrary decay equations and mark the correct alternative(s) given below.
(i)
230
92
U
→
n
+
229
92
U
(ii)
230
92
U
→
p
+
229
91
P
a
Given
M
(
230
92
U
)
=
230.033927
u
M
(
229
92
U
)
=
229.03349
u
m
n
=
1.008665
u
,
m
p
=
1.007825
,
1
a
m
u
=
931.5
M
e
V
.
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