Prove that - a sec A - b sec B - c sec Ctan A- tan B- tan C - 2R

asin A = 2R ∴ a = 2R sin #160; A ⇒2R[tan A + tan B + tan C]tan A #160; tan B #160; tan C = 2R ...

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Trigonometric Ratios

Prove that : ...

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Prove that :
$\frac{a s e c A + b s e c B + c s e c C}{t a n A . t a n B . t a n C} = 2 R$

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