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Byju's Answer
Standard X
Mathematics
Equality of Matrices
Prove that ...
Question
Prove that
a
b
c
3
+
b
c
a
3
+
c
a
b
3
>
1
a
+
1
b
+
1
c
, where
a
,
b
,
c
are different positive real numbers.
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Solution
Using A.M and G.M inequalities
a
b
c
3
+
b
c
a
3
>
2
b
a
c
…
…
(
1
)
b
c
a
3
+
c
a
b
3
>
2
c
a
b
…
…
(
2
)
c
a
b
3
+
a
b
c
3
>
2
a
b
c
…
…
(
3
)
Adding all three equations, we get
a
b
c
3
+
b
c
a
3
+
c
a
b
3
>
b
a
c
+
c
a
b
+
a
b
c
…
…
(
4
)
Similarly,
b
a
c
+
c
a
b
>
1
a
c
a
b
+
a
b
c
>
1
b
a
b
c
+
b
a
c
>
1
c
From above equations, we get
b
a
c
+
a
b
c
+
c
a
b
>
1
a
+
1
b
+
1
c
…
…
(
5
)
From
(
4
)
and
(
5
)
,
a
b
c
3
+
b
c
a
3
+
c
a
b
3
>
1
a
+
1
b
+
1
c
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0
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