1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard X
Mathematics
Trigonometric Identities
Prove that ...
Question
Prove that
cos
27
+
sin
27
cos
27
−
sin
27
=
tan
72
Open in App
Solution
L.H.S
=
cos
27
o
+
sin
27
cos
27
o
−
sin
27
=
1
+
sin
27
cos
27
1
−
sin
27
cos
27
=
1
+
tan
27
o
1
−
tan
27
o
=
tan
45
o
+
tan
27
o
1
−
tan
45
o
×
tan
27
o
=
(
tan
45
o
+
27
o
)
=
tan
72
o
=
R
.
H
.
S
(
p
r
o
v
e
d
)
.
Suggest Corrections
0
Similar questions
Q.
The value of
sin
27
∘
−
cos
27
∘
is equal to
Q.
Which of the following is the value of
sin
27
∘
−
cos
27
∘
?
Q.
s
i
n
2
1
+
s
i
n
2
89
+
c
o
s
2
7
+
c
o
s
2
83
=
?
Q.
Prove that :
cos
18
o
−
sin
18
o
=
√
2
sin
27
o
.
Q.
Evaluate :
c
o
s
e
c
2
63
∘
+
tan
2
24
∘
cot
2
66
∘
+
sec
2
27
∘
+
sin
2
63
∘
+
cos
63
∘
sin
27
∘
+
sin
27
∘
sec
63
∘
2
(
c
o
s
e
c
2
65
∘
−
tan
2
25
∘
)
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Explore more
Trigonometric Identities
Standard X Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app