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Byju's Answer
Standard XII
Mathematics
Circular Measurement of Angle
Prove that : ...
Question
Prove that :
c
o
s
30
∘
+
s
i
n
60
∘
1
+
c
o
s
60
∘
+
s
i
n
30
∘
=
√
3
2
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Solution
We have,
L
H
S
=
c
o
s
30
∘
+
s
i
n
60
∘
1
+
c
o
s
60
∘
+
s
i
n
30
∘
=
√
3
2
+
√
3
2
1
+
1
2
+
1
2
=
2
(
√
3
2
)
2
=
√
3
2
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1
Similar questions
Q.
Prove that
sin
60
∘
.
cos
30
∘
−
cos
60
∘
.
sin
30
∘
=
sin
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∘
Q.
Show that:
(i)
1
-
sin
60
°
cos
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°
=
tan
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°
-
1
tan
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°
+
1
(ii)
cos
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°
+
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1
+
sin
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°
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=
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Q.
Show that:
(i)
1
−
sin
60
∘
cos
60
∘
=
tan
60
∘
−
1
tan
60
∘
+
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(ii)
cos
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+
sin
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∘
1
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+
cos
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∘
=
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Q.
Verify each of the following:
(i) sin 60° cos 30° − cos 60° sin 30° = sin 30°
(ii) cos 60° cos 30° + sin 60° sin 30° = cos 30°
(iii) 2 sin 30° cos 30° = sin 60°
(iv) 2 sin 45° cos 45° = sin 90°
Q.
Find the value of the following
(
i
)
sin
60
∘
cos
30
∘
+
cos
60
∘
sin
30
∘
(
i
i
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cos
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cos
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–
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sin
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