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Question

Prove that: cos9xcos5xsin17xsin3x=sin2xcos10x

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Solution

L.H.S=cos9xcos5xsin17xsin3x

cosAcosB=2sin(A+B2)sin(AB2)
sinAsinB=2cos(A+B2)sin(AB2)
L.H.S=2sin(9x+5x2)sin(9x5x2)2cos(17x+3x2)sin(17x3x2)
=2sin(14x2)sin(4x2)2cos(20x2)sin(14x2)
=2sin(7x)sin(2x)2cos(10x)sin(7x)=sin2xcos10x=R.H.S.

Hence proved.

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