Prove that cosA-sinA-1cosA-sinA-1-cosecA-cotA -

LHS = cosA sinA+1cosA+sinA 1 dividing Nr and Dr by sinA we get, =cosAsinA sinAsinA+1sinAcosAsinA+sinAsinA 1sinA = cotA 1+cosecAcotA ...

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Circular Measurement of Angle

Prove that ...

Question

Prove that $\frac{c o s A - s i n A + 1}{c o s A + s i n A - 1} = c o s e c A + c o t A$ .

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\frac{c o s A - s i n A + 1}{c o s A + s i n A - 1} = \frac{1}{c o s e c A - c o t A}

\frac{c o t A + c o s e c A - 1}{c o t A - c o s e c A + 1} = \frac{1 + c o s A}{s i n A} = c o s e c θ + c o t θ = \frac{s i n A}{1 - c o s A}

\frac{cos A - sin A + 1}{cos A + sin A - 1} = cos e c A + cot A

\frac{s i n A}{1 - c o s A} = c o s e c A + c o t A

Cosa-sina+1/cosa+sina-1=coseca+cota=using the identity cosec2a=1+cot2a

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