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Question

Prove that ddx(x2a2x2+a22sin1xa)=a2x2.

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Solution

To prove ddx(x2a2x2+a22sin1xa)=a2x2
L.H.S dx(x2a2x2+a22sin1xa)
=ddx(x2a2x2)+a22ddxsin1xa
x2ddxa2x2+a2x2ddxx2+a2211(x/a)2.1a
x221a2x2+12a2x2+a22a2x2
12a2x2(a2x2)+12a2x2
a2x22+12a2x2
=a2x2
=RHS

1079284_1094807_ans_30267483eca145d5aec9f04391e0ffe0.png

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