Prove that - sin90- - -sin -tan - - 1 - -sin2 -

Let,LHS = sin (90 ^∘ #160; θ ) #160; sin θtan θ #160; 1 #160; ⇒ LHS #160; = #160; cos θ sin θ sin θ / cos θ # ...

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Chain Rule of Differentiation

Prove that : ...

Question

Prove that :
$\frac{s i n (90^{\circ} - θ) s i n θ}{t a n θ} - 1 = - s i n^{2} θ$

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