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Question

Prove that sinA1+cosA+1+cosAsinA=2cosecA

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Solution

Given, sinA1+cosA+1+cosAsinA

=sin2A+(1+cosA)2sinA(1+cosA)

=sin2A+1+cos2A+2cosAsinA(1+cosA)

=1+1+2cosAsinA(1+cosA)

=2+2cosAsinA(1+cosA)

=2(1+cosA)sinA(1+cosA)

=2sinA=2cosecA

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