Prove that sin A - 2 sin3 A 2 cos3 A - cos A - tan A

sinA 2sin^3A2cos^3A cosA =sinA ( 1 2sin^2A )cosA ( 2cos^2A 1 ) =sinA ( sin^2A+cos^2A 2sin^2A )cosA ( 2cos^2A sin^2A cos^2A ) #160; #160 ...

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Trigonometric Ratios

Prove that ...

Question

Prove that $\frac{s i n A - 2 s i n^{3} A}{2 c o s^{3} A - c o s A} = t a n A$

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\frac{sin A - 2 {sin}^{3} A}{2 {cos}^{3} A - cos A} = tan A

$\frac{s i n A - 2 s i n^{3} A}{2 c o s^{3} A - c o s A}$

p r o v e t h a t \frac{s i n A - 2 {s i n}^{3} A}{2 {c o s}^{3} A - c o s A} = t a n A

$\frac{sin A - 2 {sin}^{3} A}{2 {cos}^{3} A - cos A} =$

\frac{1 + s i n A}{1 - s i n A} = s e c A - t a n A

\frac{s i n A - 2 s i n^{2} A}{2 c o s^{3} A - c o s A} = t a n A

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