Prove that - sin x - sin 3xsin2 x - cos2 x - 2 sin x

sin x sin 3xsin ^2x cos ^2x =sin x ( 3sin x 4sin ^3x )sin ^2x ( 1 sin ^2x ) =4sin ^3x 2sin x2sin ^2x 1 =2sin x (2sin ^2x 1)2sin ^2x 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Domain and Range of Basic Inverse Trigonometric Functions

Prove that : ...

Question

Prove that : $\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x$

Open in App

Solution

Suggest Corrections

Similar questions

\frac{sin x - sin 3 x}{{sin}^{2} x - {cos}^{2} x} = 2 sin x

Prove that $\frac{sin 3 x - sin x}{cos 2 x} = 2 sin x$

Prove the following:
$\frac{sin x - sin 3x}{{sin}^{2} x - {cos}^{2} x} = 2 sin$ x.

\cos x + \cos 2 x + \cos 3 x = 0

\cos x + \cos 3 x - \cos 2 x = 0

\sin x + \sin 5 x = \sin 3 x

\cos x \cos 2 x \cos 3 x = \frac{1}{4}

\cos x + \sin x = \cos 2 x + \sin 2 x

\sin x + \sin 2 x + \sin 3 = 0

\sin x + \sin 2 x + \sin 3 x + \sin 4 x = 0

\sin 3 x - \sin x = 4 \cos^{2} x - 2

\sin 2 x - \sin 4 x + \sin 6 x = 0

\sin 3 x + \sin 2 x - \sin x = 4 \sin x \cos \frac{x}{2} \cos \frac{3 x}{2}

Join BYJU'S Learning Program