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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Multiples of an Angle
Prove that ...
Question
Prove that
s
i
n
x
1
−
c
o
s
x
=
c
o
s
e
c
x
+
c
o
t
x
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Solution
sin
x
1
−
cos
x
=
c
o
s
e
c
x
+
cot
x
solving LHS we get
sin
x
1
−
cos
x
×
1
+
cos
x
1
+
cos
x
⇒
sin
x
(
1
+
cos
x
)
1
−
cos
2
x
sin
x
(
1
+
cos
x
)
sin
2
x
=
1
sin
x
+
cos
x
sin
x
⇒
c
o
s
e
c
x
+
cot
x
=
RHS
Proved.
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Similar questions
Q.
Prove that cosecx(secx -1) - cot x(1- cosx) = sinx-sinxcosx
Q.
Prove that
tan
x
2
=
cosec
x
−
c
o
t
x
Q.
If
cosec
x
-
sin
x
=
a
3
,
sec
x
-
cos
x
=
b
3
, then prove that
a
2
b
2
a
2
+
b
2
=
1
.
Q.
If
s
i
n
x
+
c
o
s
x
+
t
a
n
x
+
c
o
t
x
+
s
e
c
x
+
c
o
s
e
c
x
=
7
and
s
i
n
2
x
=
a
−
b
√
7
, then
a
−
b
+
14
is divisible by
Q.
Solve the following equations:
(i)
sin
x
+
cos
x
=
2
(ii)
3
cos
x
+
sin
x
=
1
(iii)
sin
x
+
cos
x
=
1
(iv)
cosec
x
=
1
+
cot
x
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Standard XII Mathematics
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