MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reduction Formulae

Prove that: ...

Question

Prove that:
$2 s i n^{2} \frac{3 π}{4} + 2 c o s^{2} \frac{π}{4} + 2 s e c^{2} \frac{π}{3} = 10$

Open in App

Solution

$L H S = 2 s i n^{2} \frac{3 π}{4} + 2 c o s^{2} \frac{π}{4} + 2 s e c^{2} \frac{π}{3}$
$= 2 {sin}^{2} (π - \frac{π}{4}) + 2 {(\frac{1}{\sqrt{2}})}^{2} + 2 {(2)}^{2} = 2 {(\frac{1}{\sqrt{2}})}^{2} + 1 + 8 = 10 = R H S$

Suggest Corrections

thumbs-up

1

Similar questions

Q. Prove that :

2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

Q. Prove that :

1 + sin x = 2 {cos}^{2} (\frac{π}{4} - \frac{x}{2})

G i v e n t h a t {sin}^{2} β = sin α . cos α; s h o w t h a t cos 2 β = 2 {cos}^{2} (\frac{π}{4} + α)

Q. Prove that :

\frac{9!}{6! \times 3!} + \frac{9!}{5! \times 4!} = \frac{10!}{4! \times 6!}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Reduction Formulae

MATHEMATICS

Watch in App

explore_more_icon

Explore more

NCERT - Standard XII

Reduction Formulae

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon