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Question

Prove that cos2αcos2β+sin2(αβ)sin2(α+β)=cos2(α+β).

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Solution

Taking LHS:
cos2αcos2β+sin2(αβ)sin2(α+β)
=cos2α.cos2β+[sin(αβ)+sin(α+β)][sin(αβ)sin(α+β)]
=cos2α.cos2β4sinα.cosβ.cosα.sinβ
=cos2α.cos2βsin2α.sin2β
=cos2(α+β)

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