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Question

Prove that cosA1sinA+cosA1+sinA=2secA.

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Solution

L.H.S =cosA1sinA+cosA1+sinA

=cosA(1+sinA)+cosA(1sinA)(1+sinA)(1sinA)

=cosA+sinAcosA+cosAsinAcosA1sin2A

=2cosAcos2A=2cosA

=2secA
= R.H.S

Hence proved.

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