Prove that 1-cos-8 1-cos3-8 1-cos5-8 1-cos7-8 -1-8-

nbsp;( 1+cos nbsp;π nbsp;/ 8 nbsp;) ( 1+cos nbsp; 3π nbsp;/ 8 nbsp;) ( 1+cos nbsp; 5π nbsp;/ 8 nbsp;) ( 1+cos nbsp; 7π nbsp;/ 8 ...

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Trigonometric Ratios of Multiples of an Angle

Prove that ...

Question

Prove that $(1 + cos \frac{π}{8}) (1 + cos \frac{3 π}{8}) (1 + cos \frac{5 π}{8}) (1 + cos \frac{7 π}{8}) = \frac{1}{8} .$

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(1 + cos \frac{π}{8}) (1 + cos \frac{3 π}{8}) (1 + cos \frac{5 π}{8}) (1 + cos \frac{7 π}{8}) = \frac{1}{8}

(1 + cos \frac{π}{8}) (1 + cos \frac{3 π}{8}) (1 + cos \frac{5 π}{8}) (1 + cos \frac{7 π}{8}) = \frac{1}{8}

(1 + cos \frac{π}{8}) (1 + cos \frac{3 π}{8}) (1 + cos \frac{5 π}{8}) (1 + cos \frac{7 π}{8}) = \frac{1}{8}

(1 + c o s \frac{π}{8}) (1 + c o s \frac{3 π}{8}) (1 + c o s \frac{5 π}{8}) (1 + c o s \frac{7 π}{8}) =

Prove that $\sqrt{2 + \sqrt{2 + \sqrt{2 + 2 c o s 8 θ}}} = 2 c o s θ .$

Prove that $(1 + c o s \frac{π}{8}) (1 + c o s \frac{3 π}{8}) (1 + c o s \frac{5 π}{8}) (1 + c o s \frac{7 π}{8}) = \frac{1}{8}$

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