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Question

Prove that r1r2+r2r3+r3r1=14(a+b+c)2

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Solution

L.H.S =r1r2+r2r3+r3r1

We know r1=Δsa,r2=Δsb,r3=Δsc,r=Δs

=Δ2(sa)(sb)+Δ2(sb)(sc)+Δ2(sc)(sa)

=s(sc)+s(sa)+s(sb)=3s2s(a+b+c) using Δ=s(sa)(sb)(sc)

=3s22s2=s2=14(a+b+c)2=R.H.S.

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