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Question

Prove that every even power of every odd number is of the form 8r+1.

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Solution

Every odd number is of from 2x+1
(2x+1)2n={(2x+1)2}n=(4x2+1+4x)2={4x(x+1)+1}2
Now x(x+1) is always even which will be of form 2r
(2x+1)2n={4(2r)+1}2(2x+1)2n=(8r+1)2
Hence proved.

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