CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Circular Measurement of Angle

Prove that c...

Question

Prove that
$\frac{c o s A}{1 - t a n A} + \frac{s i n A}{1 - c o t A} = s i n A + c o s A$

Open in App

Solution

$L H S =$ $\frac{C o s A}{1 - T a n A} + \frac{S i n A}{1 - C o t A} = \frac{C o s A}{1 - \frac{S i n A}{C o s A}} + \frac{S i n A}{1 - \frac{C o s A}{S i n A}} = \frac{C o s^{2} A - S i n^{2} A}{C o s A - S i n A} = C o s A + S i n A$ $= R H S$

Suggest Corrections

thumbs-up

0

Similar questions

(1 + c o t A + t a n A) (s i n A - c o s A) = s i n A t a n A - c o t A c o s A

\frac{cos A}{1 - tan A} + \frac{sinA}{1 - cot A} = cos A + sinA .

\frac{cos A}{1 - tan A} + \frac{sin A}{1 - cot A} = sin A + cos A

\frac{1 + sin A - cos A}{c o s A + sin A - 1} = tan \frac{A}{2}

\frac{c o s A - s i n A + 1}{c o s A + s i n A - 1} = \frac{1}{c o s e c A - c o t A}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Angle and Its Measurement

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Circular Measurement of Angle

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon