Prove that : tanA−tanBcotB−cotA=tanBcotA
tanA−tanBcotB−cotA = tanA−tanB1tanB−1tanA
= tanA−tanB(tanA−tanBtanBtanA)=(tanA−tanB).tanB.tanA(tanA−tanB)
= tan B tan A = tanBcotA LHS = RHS