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Question

Prove that sin3xsinxcos2x=2 sinx

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Solution

LHS = sin3xsinxcos2x

=2 cos (3x+x2 ) sin (3xx2)cos 2 x

[ sin Csin D=2cos(C + D2)sin(C - D2)]

=2 cos 2x sinxcos 2x=2 sin x = RHS.


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