Question

Prove that if a number is trebled then its cube is 27 times the cube of the given number.

Answer 1

Let x be th number, then trebled number of x = 3x
$\therefore$ Cubing we get:
$(3x{)}^3=(3{)}^3{x}^3=27x^3$
$\therefore 27x^{3}is27$ times the cube of x i.e.e, of $x^3$