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Byju's Answer
Standard VII
Mathematics
Integers
Prove that if...
Question
Prove that if a positive integer is of the form
6
q
+
5
, then it is of the form
3
q
+
2
for some integer
q
, but not conversely.
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Solution
Let
n
=
6
q
+
5
,
where
q
is a positive integer.
We know that any positive integer is of the form
q
=
3
k
o
r
,
3
k
+
1
o
r
,
3
k
+
2
If
q
=
3
k
,
then
n
=
6
q
+
5
=
18
k
+
5
=
3
(
6
k
+
1
)
+
2
=
3
m
+
2
,
where
m
=
6
k
+
1
If
q
=
3
k
+
1
,
then
n
=
6
q
+
5
=
6
(
3
k
+
1
)
+
5
=
3
(
6
k
+
3
)
+
2
=
3
m
+
2
,
where
m
=
6
k
+
3
If
q
=
3
k
+
2
,
then
n
=
6
q
+
5
=
6
(
3
k
+
2
)
+
5
=
3
(
6
k
+
5
)
+
2
=
3
m
+
2
,
where
m
=
6
k
+
5.
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