Prove that if modulus A vector is equal to modulus B vector but vector A is not parallel to vector B then vector A-B is perpendicular to vector A+B

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\to a

\to b

| \to a + \to b | = | \to a |

2 \to a + \to b

\to b

If A vector = Axi, B vector = Byj, C vector = A vector + B vector and D vector = A vector × B vector, then C vector • D vector is equal to what

¯ ¯ ¯ a

¯ ¯ b

(¯ ¯ ¯ a + ¯ ¯ b) \times (¯ ¯ ¯ a \times ¯ ¯ b)

a

b

(a + b) \times (a \times b)

Two vector A and B have equal magnitudes. Then the vector A+B is perpendicular to.

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