Prove that in a triangle if one side is produced then exterior angle formed equal to the sum of remaining two interior angle:

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Solution

b"b'
In triangle ABC, $∠ A + ∠ B = 180^{o} - ∠ C$ ....1
$∠ A C D = 180^{o} - ∠ C$ .....2
As 1=2 therefore, $∠ A C D = ∠ A + ∠ B$
'"

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Prove that in a triangle if one side is produced then exterior angle formed equal to the sum of remaining two interior angle:

b"b'In triangle ABC,∠A+∠B=180o−∠C ....1∠ACD=180o−∠C .....2As 1=2 therefore,∠ACD=∠A+∠B'"

b"b'
In triangle ABC, $∠ A + ∠ B = 180^{o} - ∠ C$ ....1
$∠ A C D = 180^{o} - ∠ C$ .....2
As 1=2 therefore, $∠ A C D = ∠ A + ∠ B$
'"