Prove that- - 1 - - - - - - 2- 1 - - - - - - 2- - 2-

[1+θ (θ+π2)][1+θ+(θ+π2)] =[1+θ+θ][1+θ θ] =(1+θ)^2 ^2θ =1+2θ+^2θ ^2θ =1+2θ 1 =2θ ...

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Trigonometric Identities

Prove that: ...

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Prove that: $[1 + cot θ - sec (θ + \frac{π}{2})] [1 + cot θ + sec (θ + \frac{π}{2})] = 2 cot θ$

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