CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove that ∣ ∣ ∣1ωω2ωω21ω21ω∣ ∣ ∣=0

Open in App
Solution

Solving given determinant, we get

[1(ω31)ω(ω2ω2)+ω2(ωω4)] ....... as (ω3=1)

[(11)ω(0)+ω2(ωω)]

0+0+0

0

Hence proved

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon