Question

Prove that:
$\left(\frac{1}{2}\right)-2\times {\left\{{\left(3\right)}^0\right\}}^5$

Answer 1

$\frac{1}{2}-2\times {\left\{{\left(3\right)}^0\right\}}^5$

$=\frac{1}{2}-2\times 1^5$

$=\frac{1}{2}-2=\frac{1-4}{2}=\frac{-3}{2}$