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Question

Prove that: (tanθ+cscϕ)2(cotϕsecθ)2=2tanθcotϕ(cscθ+secϕ)

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Solution

L.H.S. =(tan2θ+csc2ϕ+2tanθcscϕ)(cot2ϕ+sec2θ2cotϕsecθ)
=(csc2ϕ cot2ϕ)(sec2θtan2θ)+2tanθcotϕ(cscϕcotϕ+secθtanθ)
=11+2tanθcotϕ[1/cosϕ+1/sinθ]
=2tanθcotϕ(secϕ+cscθ).

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