wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Prove that limx0exesinxxsinx=1.

Open in App
Solution

limx0exesinxxsinx (00) form
Now applying L'Hospital's rule we get,
=limx0exesinxcosx1cosx(00) form
Now applying L'Hospital's rule we get,
=limx0exesinxcos2x+esinxsinxsinx(00) form
Now applying L'Hospital's rule we get,
=limx0exesinxcos3x+esinx2.cosx.sinx+esinxsin2x+esinxcosxcosx=11+0+0+11=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of Set Operation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon