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Byju's Answer
Standard IX
Mathematics
Conditions for the Base
Prove that : ...
Question
Prove that :
log
9
14
+
log
35
24
−
log
15
16
=
0
Open in App
Solution
=
l
o
g
3
×
3
7
×
2
+
l
o
g
7
×
5
4
×
2
×
3
−
l
o
g
3
×
5
4
×
2
×
2
=
l
o
g
3
+
l
o
g
3
−
l
o
g
7
−
l
o
g
2
+
l
o
g
7
+
l
o
g
5
−
l
o
g
4
−
l
o
g
2
−
l
o
g
3
−
l
o
g
3
−
l
o
g
5
+
l
o
g
4
+
l
o
g
2
+
l
o
g
2
=
0
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0
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