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Question

Prove that:
loga2bc+logb2ac+logc2ab=0.

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Solution

Now,
loga2bc+logb2ac+logc2ab
={loga2log(bc)}+{logb2log(ac)}+{logc2log(ab)}
=2loga+2logb+2logc2(loga+logb+logc) [ Using product rule for logarithm]
=0

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