Prove that $^{n} P_{n} =^{n} P_{n - 1}$

Open in App

Solution

$^{n} P_{n} = n!$ and $^{n} P_{n - 1} = \frac{n!}{[n - (n - 1)]!} = \frac{n!}{1}$

Suggest Corrections

Similar questions

^{n} P_{n} = 2^{n} P_{n - 2}

lim n \to \infty \frac{^{n} P_{n}}{^{n + 1} P_{n + 1} -^{n} P_{n}} =

^{n} P_{n} =

What is the value of ⁿp_n?

L t n \to \infty \frac{^{n} p_{n}}{n + 1 p_{n + 1} -^{n} P_{n}} = ?

Join BYJU'S Learning Program