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Perpendicular from the Center to a Chord Bisects the Chord

Prove that pe...

Question

Prove that perpendicular drawn from the centre of circle to the chord will bisect it.

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Solution

in triangles OPL and OQL
OL = OL (Common)
OP=OQ=radius
angles OLP=OLQ=90
Hence OPL and OQL are similar triangles
Implies PL=QL
Hence prooved

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Perpendicular from the Center to a Chord Bisects the Chord

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